<u>Answer:</u>
Below!
<u>Step-by step explanation:</u>
<u>We know that:</u>
<u>Solution of Question A:</u>
<u>Percent of children: Total children/Total attendance</u>
- => 400/1500
- => 4/15
- => 0.27 (Rounded to nearest hundredth)
- => 0.27 x 100
- => 27%
<u>Hence, the percent of children is about 27%.</u>
<u>Solution of Question B:</u>
<u>Percent of women: Total women/Total attendance</u>
- => 850/1500
- => 85/150
- => 17/30
- => 17/30 x 100
- => 17/3 x 10
- => 170/3
- => 56.67%
<u>Hence, the percent of women is 56.67%.</u>
<u>Solution of Question C:</u>
- 400 + 850 + m = 1500
- => 1250 + m = 1500
- => m = 1500 - 1250
- => m = 250
<u>Percent of men: Total men/Total attendance</u>
- => 250/1500
- => 1/6
- => 0.17 (Rounded to nearest hundredth)
- => 0.17 x 100
- => 17%
<u>Hence, the percent of men is about 17%</u>
Hoped this helped.

Answer: 70.1
Step-by-step explanation:
Answer:
C)16
Step-by-step explanation:
assuming the rhombus is named ABCD and E is where the diagonals meet.
Rhombus is a quadrilateral in which
- All sides are equal
- Opposite internal angles are equal
- Diagonals bisect each other at right angles
As rhombus is ABCD , AC is a diagonal which is bisected by E (According to the properties of Rhombus)
therefore AC will be twice of AE which is given to be 8
⇒ Answer is 16
You can not put this on here :)