All categories

3 years ago

What is 13.989 to the nearest hundredth place?

Mathematics

1 answer:

Rashid [163]3 years ago

3 0

Answer:

13.99

Step-by-step explanation:

So the hundredths place is the second digit after the decimal point in this case it is 8.

So the number after it is 9 so we round up.

The number after 8 is 9

So 13.989 to the nearest hundredth place is 13.99

You might be interested in

Which value for x makes the open sentence true? 7+6•x=4^2+x^2 A.5 B.4 C.3 D.2

marusya05 [52]

You can plug in values into the equation to see which one makes it true
x=3
7+18=16+9
25=25
C. 3

4 0

3 years ago

Solve for x in the equation 2x^2 -5x+1 = 3

den301095 [7]

Plz refer to the attachment
If it helps you plzz brainliest me...

4 0

3 years ago

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

$1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297$

4 0

2 years ago

Copy the expressions which are polynomials. Give reasons why the remaining are

kupik [55]

Answer: a and c are polynomials, b is not.

Step-by-step explanation:

A polynomial p(x) is written as:

p(x) = aₙ*xⁿ + ... + a₂*x² + a₁*x¹ + a₀*x⁰

where x is the variable, and the numbers aₙ, aₙ₋₁, ..., a₁, a₀ are the coefficients of the polynomial, such that aₙ is the leading coefficient, and the value of n (always a natural number) is the degree of the polynomial.

Notice that the powers need to be always natural numbers.

Now, let's analyze the options:

a) 3*x - 2

We can rewrite this as:

3*x¹ - 2*x⁰

Then this is a polynomial.

b) p² + 1/p (in this case the variable is p)

the second term can be written as:

1/p = p⁻¹

Then we have a term with a negative power of p, this means that this is not a polynomial.

c) 3*y² - 2*y/3 + 1

Same as in the first case, we can rewrite this as:

3*y² - (2/3)*y¹ + 1*y⁰

This is a polynomial.

8 0

3 years ago

Which equation is true when n = 4? A 2n = 6 Bn+3 = 7 9- n = 13

kari74 [83]

Answer:

The answer is B. n+3=7

Step-by-step explanation:

^^^^^^^

5 0

2 years ago

Read 2 more answers