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Feliz [49]
3 years ago
8

1/6d + 2/3 = 1/4(d-2)

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0
\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2) \\ \\ \frac{d}{6}^{(2}}+\frac{2}{3}^{(4}=\frac{d-2}{4}^{(3} \\ \\ 2d+8=3(d-2) \\ \\ 2d+8=3d-6 \\ \\ 2d-3d=-6-8 \\ \\ -d=-14 \\ \\ \boxed{d=14}
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Solve for m: <br> 8(m + 2) = 3(12 - 4m)
Tema [17]

Answer:

m=1

Step-by-step explanation:

step 1: 8(m + 2) = 3(12 - 4m) remove the parentheses

step 2: 8 m + 2 = 3 12 - 4m move the terms

step 3: 8m+ 12m= 36 - 16 collect like terms and calulate

step 4: 20m=20 divide both sides

solution: m=1

3 0
3 years ago
Read 2 more answers
A cat is to receive 90 kcal of a canned food at each meal. The food has a caloric
Mnenie [13.5K]

Answer:

The cat should receive 1/5 of the can of food at each meal.

Step-by-step explanation:

Given that a cat is to receive 90 kcal of a canned food at each meal, and the food has a caloric density of 450 kcal per can, to determine what fraction of a can it should receive at each meal, the following calculation must be performed:

1 / (450/90) = X

1/5 = X

Thus, the cat should receive 1/5 of the can of food at each meal.

5 0
3 years ago
Six less than twice a number is four in algebraic expression?​
zepelin [54]

Answer:

6 < 2n = 4

Step-by-step explanation:

ig

8 0
3 years ago
Which equation is part of solving the system by substitution? 4(y + 11)2 – 3y2 = 8 4(11 – y)2 – 3y2 = 8 4(y – 11)2 – 3y2 = 8 4(–
swat32

Answer:

4(11-y)^{2} -3y^{2}=8

Step-by-step explanation:

we have

x+y=11 ----> equation A

4x^{2} -3y^{2}=8 ----> equation B

Solve the system by substitution

step 1

isolate the variable x in the equation A

x=11-y ----> equation A1

step 2

Substitute the equation A1 in the equation B

4(11-y)^{2} -3y^{2}=8

Solve for y

3 0
4 years ago
Read 2 more answers
What is the value of y in the equation 4(5y − 8 − 2) = 185 − 15? 8. 5 9. 7 10. 5 42. 5.
Bezzdna [24]

Answer:

10.5 is the answer

Step-by-step explanation:

4(5y−8−2)=185−15

(4)(5y)+(4)(−8)+(4)(−2)=185+−15(Distribute)

20y+−32+−8=185+−15

(20y)+(−32+−8)=(185+−15)(Combine Like Terms)

20y+−40=170

20y−40=170

20y−40+40=170+40

20y=210

20y/20=210/20

y=21/2

y=10.5

6 0
2 years ago
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