
When variables with exponents are divided by each other, you subtract the exponents.
For example:


Answer:
Each chord is cut into two segments at the point of where they intersect. One chord is cut into two line segments A and B. The other into the segments C and D. This theorem states that A×B is always equal to C×D no matter where the chords are.
Answer:
x = 7
Step-by-step explanation:
Given
4x - 2(x - 2) = - 4 + 5x - 13 ← distribute left side and simplify
4x - 2x + 4 = 5x - 17
2x + 4 = 5x - 17 ( subtract 5x from both sides )
- 3x + 4 = - 17 ( subtract 4 from both sides )
- 3x = - 21 ( divide both sides by - 3 )
x = 7
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Let's take this one at a time starting from the brother's net income because this would be the root basis. We let x be the number of lawns his brother and Tom mowed.
Brother's Net Income = 32x - 12x = 20x
Mitch promises to pay the borrowed money of $500 plus 40% of what his brother earns. The algebraic equation for this is:
Mitch's payment = $500 + 0.4(20x) = $500 +$8x