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liberstina [14]
3 years ago
8

Math question please answer thank you!

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0
Answer C is correct. I did the math.
matrenka [14]3 years ago
5 0
The answer is c
1 1/5 +14/5 =3
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What is 1+4<br> a)2<br> b)3<br> c)4<br> d)5
Alla [95]

Answer:

d. 5

Step-by-step explanation:

it just is trust me

8 0
3 years ago
Read 2 more answers
A sample of size 126 will be drawn from a population with mean 26 and standard deviation 3. Use the TI-84 calculator.
GenaCL600 [577]

Answer:

1. The probability that x will be more than 25 is 0.6305.

2. The 55th percentile is 26.38.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 26 and standard deviation 3.

This means that \mu = 26, \sigma = 3

1 Find the probability that x will be more than 25.

This is 1 subtracted by the p-value of Z when X = 25. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 26}{3}

Z = -0.333

Z = -0.333 has a p-value of 0.3695.

1 - 0.3695 = 0.6305.

The probability that x will be more than 25 is 0.6305.

2 Find the 55th percentile of x.

This is X when Z has a p-value of 0.55, so X when Z = 0.125.

Z = \frac{X - \mu}{\sigma}

0.125 = \frac{X - 26}{3}

X - 26 = 0.125*3

Z = 26.38

The 55th percentile is 26.38.

7 0
3 years ago
Please answer all of the questions and if u are correct I will give u brainliest ;) xoxo &lt;3
garik1379 [7]

Answer:

the answer for the 2nd question is 1/4

Step-by-step explanation:

i took the test

3 0
2 years ago
A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's avera
padilas [110]

Answer:

Option D is the correct answer.

Step-by-step explanation:

Let x be the one way distance and t be the time out.

Time taken for back = t-1

We have plane's average speed out was 300 mph and average speed on the way back was 350 mph.

That is

           \frac{x}{300}=t\texttt{ and }\frac{x}{350}=t-1

Dividing both equations

             \frac{\frac{x}{300}}{\frac{x}{350}}=\frac{t}{t-1}\\\\350t-350=300t\\\\t=7\texttt{ hours}

Time taken for back = t-1 = 7-1 = 6 hours.

Total time taken = 7 + 6 = 13 hours

Option D is the correct answer.

5 0
4 years ago
Read 2 more answers
1
KonstantinChe [14]
<h2>                     QUESTION # 1</h2>

Answer:

  • Total distance = 21 units (meters)
  • The average speed = 7 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 3 seconds, what was its average speed?

Information Fetching and Solution Steps:

  • A beetle was running along a number line.
  • The beetle ran from 4 to 25.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 4 to 25, so

the distance covered by beetle is:

                                           25 - 4 = 21 units. i.e. 21 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

as

Total distance = 21 units (meters)

Total time = 3 seconds

so

The average speed = total distance / total time

                                 = 21/3

                                 = 7 meter per second

Therefore, the average speed = 7 meter per second.

                       

<h2>                       QUESTION # 2</h2>

Answer:

  • Total distance = 54 units (meters)
  • The average speed = 6 meter per second.

Step-by-step explanation:

To Determine:

If the whole run took the bug 9 seconds, what was its average speed?

Information Fetching and Solution Steps:

  • A beetle was running along a number line.
  • The beetle ran from 24 to 78.

Let suppose each unit on a number line represents 1 meter.

As the beetle ran from 24 to 78, so

the distance covered by beetle is:

                                         78 - 24 = 54 units. i.e. 54 meters

As the average speed can be determined by dividing the total distance by the total time, so

The average speed = total distance / total time

as

Total distance = 54 units (meters)

Total time = 9 seconds

so

The average speed = total distance / total time

                                 = 54/9

                                 = 6 meter per second

Therefore, the average speed = 6 meter per second.

6 0
4 years ago
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