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Helga [31]
3 years ago
14

Numbers more than 3 units away from zero

Mathematics
2 answers:
seropon [69]3 years ago
6 0

Three unit's would be the numbers:

1, 2 and 3.


Any number you choose must be greater than 3 for example:

5, 8 or 10



Hope it helped,



BioTeacher101

Vikki [24]3 years ago
4 0
Let x represent the numbers

The numbers more than 3 units means their distance from zero is more than 3


|x|  > 3
This implies that either

x > 3
or

- x > 3
\Rightarrow x <  - 3

The solution set is the inequality

x <  - 3 \: or \: x > 3

We cannot list them
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Step-by-step explanation:

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Answer:

D. <em>a</em> = 11.71 and <em>b</em> = 15.56

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Trigonometry</u>

  • All angles in a triangle add up to 180°

<u>Pre-Calculus</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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AB = 7

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m∠B = 110°

m∠C = ?

<u>Step 2: Find missing ∠</u>

  1. Set up equation:                    m∠C + 45° + 110° = 180°
  2. Combine like terms:              m∠C + 115° = 180°
  3. Isolate unknown:                   m∠C = 25°

<u>Step 3: Find measure of </u><em><u>b</u></em>

  1. Substitute:                    \frac{sin(25)}{7} =\frac{sin(110)}{b}
  2. Cross-multiply:             bsin(25)=7sin(110)
  3. Isolate <em>b</em>:                       b=\frac{7sin(110)}{sin(25)}
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  5. Round:                          b \approx 15.56

<u>Step 4: Find measure of </u><em><u>a</u></em>

  1. Substitute:                    \frac{sin(25)}{7} =\frac{sin(45)}{a}
  2. Cross-multiply:             asin(25)=7sin(45)
  3. Isolate <em>a</em>:                       a=\frac{7sin(45)}{sin(25)}
  4. Evaluate:                       a=11.7121
  5. Round:                          a \approx 11.71
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