The time taken for the ball to fall a distance of 10feet is 1.25secs
Given the function modeled by the height expressed as:
f(t) =-16t² + 35
In order to determine the time taken by the all to fall a distance of 10 feet, hence;
f(t) = 10
10 = -16t² + 35
-16t² = 10 - 35
-16t² = -25
-t² = -25/16
t² = 25/16
t = √25/16
t = 5/4
t = 1.25secs
Hence the time taken for the ball to fall a distance of 10feet is 1.25secs
Learn more here: brainly.com/question/13881652
Answer:
26
Step-by-step explanation:
-4*2+3*4-2
16+3*4-2
16+12-2
28-2
26. PEMDAS
The height of the pole = 129.3 ft
sin 36° = height of pole/ hypotenuse
hypotenuse = 220 ft
the height of the pole = 220 sin 36° = 129.3 ≈ 129 ft
Answer:
mE=mC
mD=mB
Step-by-step explanation:
thats should be correct
