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Arisa [49]
3 years ago
6

Which of the following statement is incorrect? .

Mathematics
1 answer:
nalin [4]3 years ago
6 0

Answer:

b.Commutative property is true for subtraction of Rational numbers

Step-by-step explanation:

  • Option B is the correct answer as it is the incorrect statment in the given options.

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If you have 24 square pieces of wood, and you divided each in half. Then, you divided each of those in half. How many square pie
hichkok12 [17]
The answer is 96
24 pieces of wood all cut in half so multiply by 2
24x2=48
Now cut 48 pieces in half so multiply by 2
48x2=96
3 0
3 years ago
Jaclyn plays singles for the varsity tennis team where she won the sudden death tie breaker point with a cross-court passing sho
podryga [215]

Answer:

Incomplete question

Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.

a. Determine the pre-collision momentum of the ball.

b. Determine the post-collision momentum of the ball.

c. Determine the momentum change of the ball.

Answer:

A. 1.5353kgm/s

B. 1.6963kgm/s

C. 0.161kgm/s

Step-by-step explanation:

A. The pre-collision momentum of the ball = mass of ball × velocity of ball

Mass of ball = 57.5g = 0.0575kg

Velocity of ball = 26.7m/s

Pre-collision momentum of ball = 0.0575×26.7

= 1.5353kgm/s

B. Post collision momentum of the ball = mass of ball × velocity of ball after impact

Velocity of ball after impact = 29.5m/s

Post collision momentum of ball after impact = 0.0575×29.5

= 1.6963kgm/s

C. Momentum change of ball = momentum after impact - momentum before imlact

= 1.6963kgm/s - 1.5353kgm/s

= 0.161kgm/s

7 0
3 years ago
What is the numerator of the simplified sum?<br><br> OX+ 3<br> O 3x+6<br> O 4x+6<br> O 4x+2
Illusion [34]
The correct answer is A
5 0
3 years ago
EXTRA POINTS
lianna [129]
The slope is 1, so m = 1. 
The given point is (x,y) = (1,5) which means x = 1 and y = 5 pair up together.

Plug the three pieces of info (m = 1, x = 1, y = 5) into the y = mx+b equation. Then solve for b

y = mx+b
y = 1*x + b ... replaced m with 1
5 = 1*1 + b .... replaced x with 1, replaced y with 5
5 = 1+b
1+b = 5
b+1 = 5
b+1-1 = 5-1
b = 4

Since m = 1 and b = 4, we know that y = mx+b turns into y = 1x+4 which simplifies to y = x+4

-----------------------------------------------------------------------------------

Answer: y = x+4
8 0
3 years ago
I need help on nine and 10 instructions say to solve these equations by cross multiplying
Aneli [31]

Answer:

  9.  a = -1

  10.  b = 20

Step-by-step explanation:

The term "cross multiplying" is used to describe the appearance of the result of multiplying both sides of the equation by the product of the denominators. The result is the left numerator is multiplied by the right denominator, and the right numerator is multiplied by the left denominator. The property of equality that supports this is the multiplication property of equality, which tells you the values of the variables are unchanged if you multiply both sides by the same thing. That multiplier is chosen so that it cancels the denominators.

__

<h3>9.</h3>

  \dfrac{2a-5}{3a-4}=\dfrac{2a-3}{3a-2}\\\\(3a-2)(2a-5)=(3a-4)(2a-3)\qquad\text{"cross multiply"}\\\\6a^2 -19a +10=6a^2-17a+12\qquad\text{expand}\\\\-2=2a\qquad\text{add $19a-6a^2-12$}\\\\\boxed{a=-1}\qquad\text{divide by 2}

__

<h3>10.</h3>

  \dfrac{b-2}{b-6}=\dfrac{b+2}{b-4}\\\\(b-4)(b-2)=(b-6)(b+2)\qquad\text{"cross multiply"}\\\\b^2-6b+8=b^2-4b-12\qquad\text{expand}\\\\20=2b\qquad\text{add $6b+12-b^2$}\\\\\boxed{b=20}\qquad\text{divide by 2}

_____

<em>Additional comments</em>

Here are the answer checks:

  9. (2(-1) -5)/(3(-1)-4) = (2(-1)-3)/(3(-1)-2) ⇒ -7/-7 = -5/-5 . . . yes

  10. (10 -2)/(10 -6) = (10 +2)/(10 -4) ⇒ 8/4 = 12/6 . . . yes

__

Sometimes this method of solving the problem will result in extraneous solutions. Those will generally be values of the variable that make one or more of the denominators be zero. You must be careful to exclude those values from any possible solution set.

5 0
3 years ago
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