<span>11,550 km has to be changed to 11,550,000 meters
G · m · t² = 4 · π² · r³ we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span>
<span>
<span>
<span>
6.083*10^22
</span>
</span>
</span>
<span><span>
</span>
</span>
/
<span>
<span>
<span>
3.9</span></span></span>9 * 10^14
t^2 =
<span>
<span>
<span>
152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers
Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which <em>is 5,670 meters per second.</em>
Source:
http://www.1728.org/kepler3a.htm
Answer:
Step-by-step explanation:
How the heck imma suppose to no
Answer:
The answer is D, 43 
Step-by-step explanation:
If the pile gets bigger by 8 
each week, and you want to find out how big the pile is after 3 weeks, then you have to multiply 8 
by 3 to find out how much the pile increased by.
8 × 3 = 25 
Now, you need to add this to your initial value to get the answer.
25 + 17 = 42 
Now simplify.
43
Average speed = (distance covered) / (time to cover the distance)
= (500 miles) / (6.7 hours)
= (500 / 6.7) (mile/hour)
= 74.63 miles per hour.
I imagine there were quite a number of pit stops included in that.
This is faster than I expected when I first read your question.
That's really gettin' with it for cars in 1911 !
