Ask question

Ask question

All categories

3 years ago

12

the first Indianapolis 500 auto race took place in 1911. the winning car covered the 500 miles in 6.7 hours. what was the winnin

g cars average rate of speed in miles per hour?

1 answer:

Vesna [10]3 years ago

4 0

Average speed = (distance covered) / (time to cover the distance)

   = (500 miles) / (6.7 hours)

   = (500 / 6.7) (mile/hour)

   = 74.63 miles per hour.

I imagine there were quite a number of pit stops included in that.

This is faster than I expected when I first read your question.
That's really gettin' with it for cars in 1911 !

You might be interested in

Simplify this expression<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28a%5E8a%5E6%29%7D%7Ba%5E2%7D%20%5E%5Cfrac%7B1%7D%7B7%

kow [346]

Answer:

Step-by-step explanation: The simplification calculator allows you to take a simple or complex expression and simplify and reduce the expression to it's simplest form.

4 0

3 years ago

9. The ticket at right has a perimeter of 42 cm.

Liula [17]

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.

I've added the image of the ticket as an attachment.

(a) The missing side length

From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.

So, we have:

$Perimeter =2\times 11 + 4 \times L$

This gives

$2\times11 + 4 \times L = 42$

$22 + 4 \times L = 42$

Collect like terms

$4 \times L = 42-22$

$4 \times L = 20$

Divide both sides by 4

$L =5cm$

(b) The length of the gold lines

There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).

So, the length of the gold line is:

$Gold = 4 \times L$

$Gold = 4 \times 5cm$

$Gold = 20cm$

(c) The number of gold ink bottles.

$n = 200$ --- number of tickets

The length of all gold line in the 200 tickets is:

$Length = 200 \times Gold$

$Length = 200 \times 20cm$

$Length = 4000 cm$

$Length = 4000 \times 0.01m$ ---- convert to meters

$Length = 40m$

Given that:

$Bottle = 20m$ --- 1 bottle for 20 m

The number of bottles (n) is:

$n = \frac{Length}{Bottles}$

$n = \frac{40m}{20m}$

$n = 2$

Hence, 2 bottles of gold ink are enough.

Read more about perimeters at:

brainly.com/question/6465134

4 0

3 years ago

z 5 − z+2 2z+4 =−3 space, startfraction, 5, divided by, z, end fraction, minus, start fraction, 2, z, plus, 4, divided by, z

yan [13]

Answer:

The sum of all the possible values for z that satisfy the above equation is -5.

Step-by-step explanation:

The given equation is

$\frac{5}{z}-\frac{2z+4}{z+2}=-3$

We need to find the sum of all the possible values for z that satisfy the above equation.

The given equation can be rewritten as

$\frac{5}{z}-\frac{2(z+2)}{z+2}=-3$

Cancel out common factors.

$\frac{5}{z}-2=-3$

Add 2 on both sides.

$\frac{5}{z}-2+2=-3+2$

$\frac{5}{z}=-1$

$5=-z$

Multiply both sides by -1.

$-5=z$

Only z=-5 satisfy the given equation.

Therefore the sum of all the possible values for z that satisfy the above equation is -5.

8 0

3 years ago

A trapezoid has bases of lengths 13 cm and 17 cm. The

Vedmedyk [2.9K]

Answer:

135 cm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h(a + b)

where h is the height and a, b the parallel bases

Here h = 9, a = 13 and b = 17 , thus

A = $\frac{1}{2}$ × 9 × (13 + 17)

= 0.5 × 9 × 30

= 135 cm²

3 0

3 years ago

Which of the following equations represents a line parallel to the line given by y=5x +9?

erma4kov [3.2K]

Answer:

y = 5x + 1

Step-by-step explanation:

Lines that are parallel to each other on a graph would have the same slope but different y-intercepts. When option A's equation is graphed along with the line given in the question, the lines appear to be parallel.

Option A should be the correct answer.

7 0

3 years ago