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Monica [59]
3 years ago
9

Solve the equation:

Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0

Answer:

x=1 is the correct answer

aev [14]3 years ago
6 0
The answer is A because it has many solutions
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Harrison made a building using 124 blocks Greyson made a building using 78 blocks how many more blocks did Harrison use than Gre
enyata [817]
124 - 78 = 46.....Harrison used 46 more blocks then Greyson
6 0
4 years ago
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Need help with math question. Please. I’ll give 5 stars
TiliK225 [7]

Answer:

The domain is -11 < x < 4 or in interval notation it is (-11, 4).

Step-by-step explanation:

The domain is the set of possible values of x.

Here the open circles at each end mean that these values are not included.

8 0
3 years ago
If a number is chosen at random from the set {1, 2, 3, 4, . . ., 18}, what is the probability that the number chosen is a factor
choli [55]
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.

P (probability) = possible outcomes / total outcomes

It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:

P(A or B) = P(A) + P(B)

All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.

P(1 or 17) = P(1)/18 + P(1)/18

P(1 or 17) = 2/18

Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.

2/18 simplifies to 1/9


So, your answer is 1/9
5 0
2 years ago
What additional information could be used to prove ABC MQR using SAS?
Igoryamba

Answer:

To prove that ΔABC ≅ ΔMQR using SAS, we show that two sides with the intersection angle are congruent.

From the diagram, it is shown that CA is congruent to RM.

From the first option, given that m∠A = 64° and AB = MQ = 31 cm, then we have CA = RM, AB = MQ, and CAB = RMQ (i.e. m∠A = m∠M = 64°).

This shows that the first option is correct.

From the second option, given that CB = MQ = 29 cm, then we have CA = RM, CB = MQ, but ACB is not congruent to RMQ.

Thus the second option in not correct.

From the third option, m∠Q = 56° and CB ≅ RQ, then we have CA = RM, CB = RQ, ACB = 60°, but we do not know the value of MRQ.

Thus the third option is not correct.

From the fourth option, m∠R = 60° and AB ≅ MQ, then we have CA = RM, AB = MQ, RMQ = 64°, but we do not know the value of CAB.

Thus the fourth option is not correct.

From the fifth option, AB = QR = 31 cm, then we have CA = RM, AB = QR, but we do not know the value of CAB or MRQ.

Thus, the fifth option is not correct.

Therefore, the additional information that could be used to prove ΔABC ≅ ΔMQR using SAS is m∠A = 64° and AB = MQ = 31 cm

6 0
3 years ago
I am larger than 6. To the nearest whole, I round down not up. My ones digit is odd, but my tenths digit is even
Anastaziya [24]
7.4 are you supposed to make up a number??
5 0
3 years ago
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