Math question. PLEASE HELP. I really need it
2 answers:
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Answer:
942
Step-by-step explanation :
so your d is 300 so your r = 300/2= 150
a=3.14*r*r= 3.14*150*150= 70650
c= 3.14*d= 3.14*300= 942
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OR
The curved surface area of solid cylinder is
As we are given that:
Diameter of solid cylinder = 8 cm
Length or Height o solid cylinder = 140 cm
Formula used to calculate the curved surface area of cylinder is:2n x h
Curved surface area of cylinder =2r x h
where,
r = radius of cylinder
h = height or length of cylinder
Radius of cylinder = daimeter
Now putting all the given values in above formula, we get:
Curved surface area of cylinder = 2x 22/7 x 140cm
Curved surface area of cylinder =
Therefore, the curved surface area of solid cylinder is3520cm^{2}
Answer:
1 solution
Step-by-step explanation:
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, is equal to
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, . Since a and b were generic elements of H, then H/G is abelian.