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Andru [333]
3 years ago
11

Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}

Mathematics
2 answers:
stepan [7]3 years ago
7 0

We are given order pairs  (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.

We need to remove in order to make the relation a function.

<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>

In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.

<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>
Alex17521 [72]3 years ago
3 0
I'm gonna say (0,8) because there can't be two of the same x values in a function.
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3 years ago
Which of the following equations has the same solution as m - (-62) = 45?
Alborosie
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If you help me I’ll love you forever &lt;3
eimsori [14]

Answer:

translation

Step-by-step explanation:

because a reflection across the x-axis is not right, and neither is across the y-axis. The triangle was also not rotated 90 degrees. It was translated 8 units to the right and 4 units up.

5 0
3 years ago
The ratio of fish to ducks at the water's edge was 5 to 2. If there were 28 in all, how many were fish?
densk [106]

Answer:

20 fish.

Step-by-step explanation:

Convert ratio to fraction:

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8 0
3 years ago
Write (1/3i)-(-6+2/3i) as a complex number in standard form
Eddi Din [679]

Answer:

6+\frac{i}{3}

Step-by-step explanation:

\frac{1}{3\imath}-(-6+\frac{2}{3\imath})

\frac{1}{3\imath}+6-\frac{2}{3\imath}

taking like terms together

\frac{1}{3\imath}-\frac{2}{3\imath}+6

taking LCM

\frac{1-2}{3\imath}+6

\frac{-1}{3\imath}+6

taking LCM

\frac{-1+18\imath}{3\imath}

splitting the term

\frac{-1+18\imath}{3\imath}

splitting the term

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-\frac{1\times3\imath}{3\imath \times \imath}+6

-\frac{i}{3\imath^2}+6

we know that

\imath^2=-1

putting this value in above equation

\frac{\imath}{3}+6

7 0
3 years ago
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