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3 years ago

What is the length of AB when A is (-7,-6) and B is (1,0)

Mathematics

1 answer:

NemiM [27]3 years ago

5 0

Answer:

The answer is

<h2>10 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{( {x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A (-7,-6) and B (1,0)

The distance between them is

$|AB| = \sqrt{( { - 7 - 1})^{2} + ({ - 6 - 0})^{2} } \\ = \sqrt{ ({ - 8})^{2} + ({ - 6})^{2} } \\ = \sqrt{64 + 36} \\ = \sqrt{100} \: \: \: \: \: \: \: \:$

We have the final answer as

<h3>10 units</h3>

Hope this helps you

You might be interested in

There are 100 people in a sport centre.

Arlecino [84]

We need to determinate who doesn't use anything, so first we must know the real number of who are practising: a person can do more things.

For doing this, is better use a three-circles graphic, but we try to do without it.

16 pool + gym + track, and this number is sure

38 gym + pool, but this number includes the people of 1st point. We must know who do only gym + pool: 38 - 16 = 22

31 pool + track, this number also includes people of 1st point, so: only pool + track 31 - 16 = 15

33 gym + track, this number also includes people of 1st point, so: only gym + track 33 - 16 = 17

now:

67 gym, we must know who use only gym: 67 - 16 (gym + pool + track) - 22 (gym + pool) - 17 (gym + track) = 12

62 pool, we must know who use only pool: 62 - 16 (gym + pool + track) - 22 (gym + pool) - 15 (pool + track) = 9

56 track, we must know who use only track: 56 - 16 (gym + pool + track) - 15 (pool + track) - 17 (gym + track) = 8

now we must now who do some facility: let's sum all

16 + 22 + 15 + 17 + 12 + 9 + 8 = 99

99/100 practise something

So only 1/100 doesn't use nothing

The probability is 1%

7 0

2 years ago

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio, si avanza medio kilómetro en bus y lo demás a pie ¿

Murljashka [212]

Answer:

Al estudiante le falta caminar $\frac{1}{3}$ de kilómetro.

Step-by-step explanation:

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción $\frac{2}{3}$ .

El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción $\frac{1}{2}$ , por lo tanto un medio es la mitad de una cantidad. Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:

$\frac{1}{2} *\frac{2}{3}$

Resolviendo:

$\frac{1}{2} *\frac{2}{3} =\frac{1*2}{2*3} =\frac{2}{6} =\frac{1}{3}$

Entonces, la distancia recorrida en bus es $\frac{1}{3}$ de kilómetro.

Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:

$\frac{2}{3} - \frac{1}{3}$