B because if there are 10 large dogs and that is two times the number of small dogs than there are half as many small dogs as big doge which would mean the equation is D=1/2(10)+10.
Answer:
3r^2 /2
Step-by-step explanation:
r^3 cancels out r in the denominator remaining with r^2 in the numerator.
so 3r^2/2
= 3r^2 /2
Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).
Let <em>x</em> be the inverse. Then <em>x</em> is such that
23<em>x</em> ≡ 1 (mod 1000)
Use the Euclidean algorithm to solve for <em>x</em> :
1000 = 43×23 + 11
23 = 2×11 + 1
→ 1 ≡ 23 - 2×11 (mod 1000)
→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)
→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)
→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)
→ 23⁻¹ ≡ 87 (mod 1000)
Answer:
(x+4)(x-5)
Step-by-step explanation:
You need to find two numbers that multiply to be -20 but add up to be -1.
