Step-by-step explanation:
5(tanx)^2 -2 +tanx=0
let tanx=y
5y^2 + y-2=0
y=0.5403 or y= -0.7403
tanx=0.5403
x=arctan(0.5403)
x=28.38°
or
tanx=-0.7403
x=arctan(-0.7403)
x=143.49°
I'm going to use the slope formula which is
m = (y2 - y1)/(x2 - x1)
where (x1,y1) and (x2,y2) are the two points the line goes through
Slope of line PQ
m = (y2 - y1)/(x2 - x1)
m = (-6 - 8)/(-5 - (-7))
m = (-6 - 8)/(-5 + 7)
m = (-14)/(2)
m = -7
The slope of line PQ is -7
Slope of RS
m = (y2 - y1)/(x2 - x1)
m = (0 - (-5))/(-2 - 3)
m = (0 + 5)/(-2 - 3)
m = (5)/(-5)
m = -1
The slope of line RS is -1
Because the slopes are NOT equal (one is -7 and the other is -1), this means the lines are NOT parallel.
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Answer: Choice B) No, the lines have unequal slopes
Answer:
True
Step-by-step explanation:
The answer to your question is 30
Send it to me and I'd be happy to help! :)
