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3 years ago

Find a number less than 3000 which has a remainder of 30 when divided by 32, and a remainder of 44 when divided by 58.

Mathematics

1 answer:

melisa1 [442]3 years ago

6 0

798 yeah your welcome if im wrong...... sorry i guess

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Which of the following is true for the relation f(x) = x2 + 8? Only the inverse is a function. Both the equation and its inverse

Alchen [17]

ANSWER

Only the equation is a function

EXPLANATION

$f(x)=x^2+8$ is graphed above with its inverse $f^{-1}(x)=\pm \sqrt{x-8}$ .

We perform the vertical line test for both the equation and its inverse.

The equation $f(x)=x^2+8$ passed the vertical line hence it is a function.

However, $f^{-1}(x)=\pm \sqrt{x-8}$ failed the vertical line test, hence it is not a function.

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3 years ago

Calculate the quotient below and give your answer in scientific notation.

ELEN [110]

Answer: 8.16•10^2

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

. The sign of the exponent will depend on the direction you are moving the decimal. You do this to both equations and when you got the final answer of you divide the 2 equations and put it back in scientific notation Mark me brainliest

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3 years ago

Read 2 more answers

4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep

bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.92}{2} = 0.04$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.04 = 0.96$ , so Z = 1.88.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that $\sigma = 2.2$

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1 = 1.88\frac{2.2}{\sqrt{n}}$