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laiz [17]
3 years ago
9

Destiny's age is 3 less than three times Cedric's age. The sum of their ages is 57. How old is Destiny?

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0
Destiny is 27 years old 

10x3=30 
30-3=27
27+30=57
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The sum of two consecutive multiples of 9 is 63 .Find these multiples​
san4es73 [151]

Step-by-step explanation:

divide 63 from 9

=the answer is 7

7 0
3 years ago
State the value of the discriminant of -6x^2 +2x + 3 = 0
Dmitry [639]

Answer:

76

Step-by-step explanation:

recall that for a quadratic equation in the form

ax² + bx + c = 0, the discriminant is given by

discriminant, D = b²- 4ac

we are given the following:

-6x² + 2x + 3 = 0,

comparing this with the general equation above, it is clear that,

a = -6, b = 2 and c = 3,

substituting these into our equation for discriminant:

D = b²- 4ac

= 2² - 4(-6)(3)

= 4 + 72

= 76

4 0
3 years ago
Holler sold 150 frozen yogurts. Out of these frozen yogurts sold, 40% included toppings. How many frozen yogurts included toppin
Colt1911 [192]
60. 40 percent of 150 yogurts comes to a sum of 60
5 0
2 years ago
Find the equation of the line shown.
tia_tia [17]

y=1x+6, because the formula is y=mx+b.

4 0
2 years ago
Read 2 more answers
Will rate7 you brainliest
Vilka [71]

Answer:

\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)

\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)

\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)

\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)

Now, let's compute the product.

\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}

So the correct answer is the first one.

Thank you.

7 0
3 years ago
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