All categories

2 years ago

How will you write 7^5 as a multiplication expression?

Mathematics

1 answer:

Margarita [4]2 years ago

3 0

I think it can be written as 7×7×7×7×7

You might be interested in

A courier service advertises that its average delivery time is less than six hours for local deliveries. A random sample of size

Diano4ka-milaya [45]

Answer, Step-by-step explanation:

According to the exercise, we evaluate the delivery time of a courier company and we will hypothesize the best case with a sample size of 10, which is:

Small sample T test for single mean

The hypothesis that we will develop will be the following:

null hypothesis = mu> = 6

hypothesis alternativa: <6

3 0

2 years ago

Use trianglePQR to write the trigonometric ratio as a decimal. round to four decimal places.

astraxan [27]

I hope this answer helps, it’s kinda messy, but it’s still understandable (I guess)

4 0

2 years ago

Javier rode his bike for a total of 40 minutes. The number of minutes he rode after lunch is 4 times the number of minutes he ro

Greeley [361]

Javier rode his bike for a total of 40 minutes.

Let x be the minutes Javier ride after lunch

Let y be the minutes Javier ride before lunch

The number of minutes he rode after lunch is 4 times the number of minutes he rode before lunch

x = 4 y

The number of minutes he rode after lunch + number of minutes he rode before lunch = 40

x + y = 40

We know x= 4y

4y + y = 40

5y = 40

y = 8

x= 4y so x= 4(8) = 32

Javier ride 32 minutes after lunch

7 0

2 years ago

The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (

sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

$\dfrac{dr}{dt} = 1\text{ meter per hour}$

The height is decreasing at a rate 4 meter per hour

$\dfrac{dh}{dt} = -4\text{ meter per hour}$

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

$\pi r^2 h$

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

$\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}$

Putting all the values we get,

$\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8$

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.

3 0

2 years ago

Pleas help me please and than you! (6th grade math)

klasskru [66]

Answer:

wow u call that 6th grade

Step-by-step explanation:

I am in 8th grade and dont get this at all.

never touched the topic

6 0

2 years ago