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2 years ago

What is 3/8 written as a percent? 3/8 = 0.375 * 100 = 37.5%

2 answers:

5 0

If you would like to know what is 3/8 written as a percent, you can calculate this using the following steps:

3/8 = 375/1000 = 0.375
0.375 * 100 % = 37.5%

The correct result would be 37.5%.

melomori [17]2 years ago

5 0

To convert a fraction to a percentage, multiply it by 100 and add the percent (%) sign.

$\frac{3}{8}\times 100 = \frac{300}{8} =\frac{150}{4} =\frac{75}{2} = 37.5$

So 3/8 is 37.5%.

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In a data set with a normal distribution the main is 59 and standard deviation is three about what percent of the data live betw

jolli1 [7]

Answer:

81.9%

Step-by-step explanation:

In a data set with a normal distribution the mean is 59 and standard deviation is three about what percent of the data live between 53 and 62

Using z score formula

z = (x-μ)/σ, where

x is the raw score,

μ is the population mean = 59

and σ is the population standard deviation = 3

For x = 53

z = 53 - 59/3

= -2

P-value from Z-Table:

P(x = 53) = 0.02275

For x = 62

z = 62 - 59/3

= 1

P-value from Z-Table:

P(x = 62) = 0.84134

Hence, the probability of the data live between 53 and 62 is

0.84134 - 0.02275

0.81859

Converting to Percentage.= 0.81859

× 100 = 81.859%

Approximately = 81.9%

6 0

3 years ago

Olivia has $250.00 when she opens her cupcake shop inthe morning. she sells each cupcake for $3.50.

Kipish [7]

.... how many cup cakes does Olivia have? 250/3.50 = more or less 71

5 0

2 years ago

Read 2 more answers

Two angles of a triangle measure 15° and 85°. What is the measure for the third angle

andrezito [222]

Answer: 80°

Step-by-step explanation:

The sum of the angles in a triangle is 180°. Since the two angles of a triangle measure 15° and 85°.

The measure for the third angle will be:

= 180° - (15° + 85°)

= 180° - 100°

= 80°

The third angle is 80°

4 0

2 years ago

If c=5 and d=4<br> what is 6c squared minus 5d plus 8?

Ymorist [56]

6c^2-5d+8
6 (5)^2-5(4)+8
30^2-20+8
900-20=8
880-8=872
ANSWER:872

5 0

2 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

2 years ago

Read 2 more answers