F, A.
-3, 1
use a graphing calc
or do
x+3 = 0 or x-1 = 0 to get x = -3 or x = 1
Answer:
Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.
Step-by-step explanation:
HOPE THIS HELPS! :)
Let's solve your equation step-by-step.
x=−15−6x−2
Step 1: Simplify both sides of the equation.
x=−15−6x−2
x=−15+−6x+−2
x=(−6x)+(−15+−2)(Combine Like Terms)
x=−6x+−17
x=−6x−17
Step 2: Add 6x to both sides.
x+6x=−6x−17+6x
7x=−17
Step 3: Divide both sides by 7.
7x/7= -17/7
x= -17/7
Answer:
x= -17/7
Answer:
Step-by-step explanation:
The image A’B’C’ is scaled down by a factor of 1/3
Answer:
-7/20
Step-by-step explanation:
8/20+-15/20=-7/20