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leonid [27]
4 years ago
14

What is the equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is y=5/4 x-

2?

Mathematics
2 answers:
liubo4ka [24]4 years ago
8 0
Hey there :)

y = \frac{5}{4}x - 2
Slope is the coefficient of x ⇒ \frac{5}{4}

If the second line is perpendicular to the given line, then the slope of the 2nd line is the reverse/reciprocal of the 1st line ⇒ \frac{4}{5}

(10, 5)
  ↑  ↑
  x₁ y₁

Point-slope form is ( y - y₁ ) = m ( x - x₁ )

y - 4 = \frac{4}{5} ( x - 10 )
y - 4 = \frac{4}{5} x - 8

y = \frac{4}{5} x - 4 ⇔ The equation of the line that passes through the point (10,5) ans perpendicular to the given line




Ad libitum [116K]4 years ago
5 0

Answer:

Question with point (10,5)

y=-4/5x+13


Slope of the perpendicular line would be the NEGATIVE reciprical!

Step-by-step explanation:

The answer above is good (except for forgetting it is the negative reciprical) and the person used the point (10,4) not (10,5) from the question...

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