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4 years ago

Venla is 5 years older than her cousin Kora. Write an equation for the age of Venla, v, when Kora is k years old.

Mathematics

2 answers:

never [62]4 years ago

6 0

Answer:

v = k +5

age is 13

Step-by-step explanation:

Talja [164]4 years ago

5 0

K + 5 =V
Kiena + 5 years = Venus’s age

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What is an equation for a circle with a center at (-2,3) and a radius of 3

neonofarm [45]

Answer:

(x+2)² + (y–3)² = 3²

Step-by-step explanation:

just use the standard formula

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4 years ago

Find the value of x. Show all of your work!

Georgia [21]

Answer:

145⁰

Step-by-step explanation:

180 minus 73⁰ plus 62⁰

which is 180 minus 135

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3 years ago

Please help me with the 3rd question!!! I'll give you 91 points now, please.

saw5 [17]

Answer:

At the end of the day 797 lockers were closed.

Step-by-step explanation:

So first of all you need to find out how many even numbers there are from 1-900 (which is 450) so you know that 450 are open. In the 3 multiplication tables every second number is even so you know that half of the 450 lockers that was opened was closed again: this meant that 225 lockers remained open.

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4 years ago

Chris bought 4 hot dogs for $1.50. Which of the following shows an equivalent rate?

o-na [289]

Answer:

1 hot dog for$0.50

Step-by-step explanation:

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3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):