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3 years ago

Someone help me please

Mathematics

2 answers:

Lena [83]3 years ago

5 0

Since this can be divided into similar triangles, x is 1/3 of 6 and y is 2/3 of 6.
x=6(1/3) =2
y=6(2/3) = 4

gogolik [260]3 years ago

3 0

x/5 = 6/15
15x = 30
x = 2

answer
x = 2 ft

y/10 = 6/15
15y = 60
y = 4

answer
y = 4 ft

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What is x if the volume of<br> the box is 70 in^3 ?

kirza4 [7]

Answer:

12.25.

Step-by-step explanation:

1) the formula of the volume given in the condition is:

V=2*2/7*10x.

2) If V=70, then

2*2/7*10x=70, where x=12.25.

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2 years ago

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3 years ago

Type a digit that makes this statement true.

posledela

The possible digits that will make 14, 213, 1__2 to be divisible by 4 are;

1, 3, 5, 7 and 9

<h3>Divisibility of Numbers</h3>

We are given the digit as 14, 213, 1__2.

Now, we see that the first of the last two digits is blank and for the give digit 14, 213, 1__2 to be divisible by 4 then the last two digits must be divisible by 4.

Now, since the last 2 digits must be divisible by 4, then it means any singe digit odd number we put in the blank space will yield a combined digit that is divisible by 4. Let us check them;

For 1; 14, 213, 112 ÷ 4 = 3, 553, 278

For 3; 14, 213, 132 ÷ 4 = 3, 553, 283

For 5; 14, 213, 152 ÷ 4 = 3, 553, 288

For 7; 14, 213, 172 ÷ 4 = 3, 553, 293

For 9; 14, 213, 192 ÷ 4 = 3, 553, 298

Read more about divisibility of numbers at; brainly.com/question/24672369

7 0

3 years ago

Read 2 more answers

Omar is on a diet to lose some weight. He is losing weight at a rate of 2 pounds per week. After 6 weeks, his weight is 204 poun

bekas [8.4K]

Our basis would be 204 pounds. His original weight, 6 week ago, must be

204 + 2(6) = 216 pounds

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$Target \ weight = \ Present \ weight \ -2(number \ of \ weeks)$

189 = 204 - 2(number of weeks)
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The total number of weeks would then be 6 weeks + 7.5 weeks. It would take Omar 13 and a half weeks since he started his diet to reach his target weight.

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4 years ago

A pilot spots the airport at an angle of depression of 16°. The plane is flying at an altitude of 9,000 ft. What is the ground d

antiseptic1488 [7]

Answer:

$31,387\:\text{ft}$

Step-by-step explanation:

We can form a right triangle using the plane, the airport, and ground and use basic trig for a right triangle to solve this problem.

In a right triangle, $\tan\theta=\frac{\text{opp}}{\text{adj}}$ . Therefore, we have the following equation, where $x$ is ground distance between the plane and the airport:

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3 years ago