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antoniya [11.8K]
4 years ago
12

Write an equation of a line that passes through (-12, -14) with slope 6.

Mathematics
1 answer:
damaskus [11]4 years ago
6 0

The slope intercept form of a line is y = mx + b

  • m = slope
  • b = y-intercept

Plug in the slope, 6, into m.

Rewrite the equation;

  • y = 6x + b
  • We need to find b, your y-intercept, to finish this equation.

Plug in your point coordinate, (x, y) ⇒ (-12, -14) into the equation.

  • -14 = 6(-12) + b

Solve for b to find the y-intercept.

  • -14 = -72 + b
  • 58 = b

Your new equation (your answer) is<em> </em>y = 6x + 58.

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3 0
4 years ago
What is the rate of change of y with respect to x for this function?<br> HELP FOR BRAINLYEST
Pepsi [2]
First let's assume that the table contains points on a straight line.  Then all we have to do is to determine the slope of that line.

Suppose we go from (0,3) to (7,-28.5).
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Then the slope, m, is m = ------------- = ---------- = - 9/2, or - 4.5.
                                              7-0              7

Let's check this result!

Suppose that y = mx + b governs the relationship between x and y.


Then y = -4.5x + b

suppose we find b by substituting the coordinates from the point (0,3):

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Then b = 3, and y = -4.5x + 3.  Does the point (-2,12) satisfy this equation?

Does 12 = -4.5(-2) + 3?  Does 12 = 9 + 3?  YES.

So y = -4.5x + 3 is the equation from which these points came, and the rate of change of y with respect to x is the slope m = -4.5, or m = -9/2.

6 0
3 years ago
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