A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
Answer:
Step-by-step explanation:
x is the cherries eaten
It would be 11 if I’m reading this right
Answer:
(- 3, 5 )
Step-by-step explanation:
Given the 2 equations
y = - x + 2 → (1)
y = - 2x - 1 → (2)
Using substitution method.
Substitute y = - x + 2 into (2)
- x + 2 = - 2x - 1 ( add 2x to both sides )
x + 2 = - 1 ( subtract 2 from both sides )
x = - 3
Substitute x = - 3 into (1)
y = - (- 3) + 2 = 3 + 2 = 5
Solution is (- 3, 5 )