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Dmitrij [34]
3 years ago
8

Jack leased a car for $159/month for 36 months. The amount due when he signed the lease was $2399. How much did Jack pay during

the first year of the lease?
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
6 0
Quick question before I answer: Did he have to pay $2,399 when he signed the lease, or was that just how much he had to pay in total over the course of 36 months?
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Answer:It looks to me like you answered it and made it look like you did not.

Step-by-step explanation:

The page is darker than where the answer is.

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6 0
3 years ago
Ming works as a quality assurance analyst at a bottling factory. She wants to use a one-sample z interval to estimate what propo
Nastasia [14]

Answer:

Sample size is n=423

Step-by-step explanation:

Given that,

Margin of error =4%

Confidence level =90%

Suppose, sample proportion=0.5

        i.e. \hat{P}=0.5

We know that,

     Margin of error =2^*\sqrt{\frac{\hat{p}(1-\hat{p})}{n} }

 ∴ 1.64\sqrt{\frac{0.5(0.5)}{n} } \leq 4\%

\Rightarrow 1.64\sqrt{\frac{0.25}{n} } \leq 0.04

\Rightarrow \frac{0.5}{\sqrt{n} } \leq \frac{0.04}{1.64}

\Rightarrow \frac{0.5}{\sqrt{n} } \leq 0.0243

\Rightarrow \sqrt{n}\geq \frac{0.5}{0.0243}

\Rightarrow \sqrt{n}\geq 20.57

squaring on both side,

∴ n=423.1249

Hence, the sample size is,

   n=423

Hence, the correct option is (b).

       

7 0
3 years ago
Find the value of x.<br> helpppp
Bezzdna [24]

Answer: 55^{\circ}

Step-by-step explanation:

The measure of the third unknown arc is

360^{\circ}-70^{\circ}-110^{\circ}=180^{\circ}.

So, x=\frac{180^{\circ}-70^{\circ}}{2}=\boxed{55^{\circ}}

8 0
2 years ago
The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
3 years ago
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