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3 years ago

2 1/4 x 3 2/5 show all your work

Mathematics

1 answer:

monitta3 years ago

5 0

Answer:

153/20

Step-by-step explanation:

I assume you're asking

$2 \frac{1}{4} \times 3 \frac{2}{5}$

$\frac{9}{4} \times \frac{17}{5}$

$\frac{153}{20}$

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On considère les deux expressions A et B. A=4(x+5)-8 B=x au carré+15. Avec x=1,puis avec x=3, je trouve le même résultat pour A

Ainat [17]

Explication étape par étape:

Compte tenu des expressions ';

A = 4 (x + 5) -8

B = x² + 15

Nous devons vérifier si A = B pour les deux valeurs de x à x = 1 et x = 3

à quand x = 1

A = 4 (1 + 5) -8

A = 4 (6) - 8

A = 24-8

A = 16

B = x² + 15

B = 1² + 15

B = 1 + 15

B = 16

Donc à quand x = 1, A = B = 16

quand x = 3

A = 4 (x + 5) -8

A = 4 (3 + 5) -8

A = 4 (8) - 8

A = 32-8

A = 24

B = 3² + 15

B = 9 + 15

B = 24

Également lorsque x = 3, A = B = 24

Cela montre que le postulat d'Emmas est juste.

5 0

3 years ago

PLZ HELP HURRY!!! HAVE A DEADLINE!!!

Lynna [10]

Answer:

y = -2x - 6

The y-intercept will be (0,-6)

One point will be at (1,-8)

The line will go downward since it is a negative slope

Step-by-step explanation:

y−2=−2(x+4)

Distribute

y - 2 = -2x - 8

Move the constant to the other side

y - 2 = -2x - 8

+2 = +2

y = -2x - 6

8 0

4 years ago

Plz help me I’ll give brainliest

Katarina [22]

Answer:

I would maybe be able to help if it wasn't so blurry

4 0

3 years ago

The curves r1(t) = 4t, t2, t3 and r2(t) = sin(t), sin(5t), 2t intersect at the origin. find their angle of intersection, θ, corr

san4es73 [151]

First get the tangent vectors by differentiating r1 and r2
$r_1 '(t) = (4,2t,3t^2) \\ \\ r_2'(t) = (cos (t), 5 cos(5t), 2)$
Evaluate at t=0
$r_1' = (4,0,0) \\ \\ r_2' = (1,5,2)$

Use identity for angle between 2 vectors:
$u*v = |u| |v| cos \theta$

Evaluate dot product and unit vectors:
$u*v = (4,0,0)*(1,5,2) = 4 \\ \\ |u| = \sqrt{4^2 +0^2+0^2} = 4 \\ \\ |v| = \sqrt{1^2 + 5^2+2^2} = \sqrt{30}$

Sub into identity and solve for theta:
$4 = 4 \sqrt{30} cos \theta \\ \\ cos\theta = \frac{1}{\sqrt{30}} \\ \\ \theta = 79.48$

Answer:
Angle of intersection is about 79 degrees.

5 0

4 years ago

The tires of a go-kart are 1 m in circumference. The tires revolve 15 times per second.

Goryan [66]

Answer:

600

Step-by-step explanation:

The circumference of a tire is the distance around it. The distance around these tires is 1 m. Since the tires revolve 15 times per second, this means every second the tires travel 15 m. This means that in 40 seconds, the tires travel15(40) = 600 m.

15 x 40 = 600

4 0

4 years ago

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