Answer:
Explanation:
Given
First bicycle travels 6.10 km due to east in 0.21 h
Suppose its position vector is 

After that it travels 11.30 km at
east of north in 0.560 h
suppose its position vector is 

after that he finally travel 6.10 km due to east in 0.21 h
suppose its position vector is 

so position of final position is given by



t=0.21+0.56+0.21=0.98 h


For direction

w.r.t to x axis
Answer:
12N
Explanation:
Force acting on any body is equal to mass of body multiplied by acceleration produced in the body.
Its formula is
F = M*a
where F is the force acting on body
M is the mass of the body
a is the acceleration produced in the body
Unit of force is Newton represented by N
1 N is force acting on body of mass 1 kg which produces acceleration of 1m/s^2.
_____________________________________
Given
a = 0.50 m/s^2
M = 24 kg
therefore
F = 24*0.5 = 12 N
Thus, magnitude of the boy's pushing force is 12 N.
Answer:
.000828 j
Explanation:
Work = F * d
.0069 N * .12 m = .000828 j