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Strike441 [17]
3 years ago
8

A 55- kg woman has a momentum of 220 kg.m/s. What is her velocity?

Physics
1 answer:
exis [7]3 years ago
6 0

Answer:

P=mv

Momentum=mass*velocity

Mass=55kg

Velocity=?

Momentum=220kg.m/s

P=mv

v=p/m

v=220/30

v=7.33m/s

Explanation:

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El peso normal de un estudiante de secundaria es 725 N y el área de los dos zapatos que usa es de 412 cm2 . La presión medida qu
kotykmax [81]

Answer:

Presión = 175,97 N/m²

Explanation:

Dados los siguientes datos;

Peso del alumno (fuerza) = 725N

Área de zapatos = 412 cm² a metros cuadrados = 412/100 = 4.12 metros

Para encontrar la presión, usaríamos la siguiente fórmula;

Presión = fuerza / área

Presión = 725 / 4.12

Presión = 175,97 N/m²

8 0
3 years ago
What is hard but flexible structure is found in the nose and ears
avanturin [10]
<span>Cartilage is the hard but flexible structure found in pieces of your nose and ears. It is similar to bone, but allows for flexibility and movement. When looking at skeletons, you'll notice that they don't have a nose or ears, because cartilage deteriorates much faster than bone. Cartilage is also found in elsewhere in the animal kingdom--the skeletal structure of a shark is made primarily from cartilage!</span>
4 0
3 years ago
Can somebody explain it to me please?​
Volgvan

Answer:

45°.

It is a property of the parabolas.. When the angle between a parabola and the x-axis is 45° the range is maximum.

6 0
3 years ago
Read 2 more answers
A particle moves along the x axis from the origin. The magnitude of the position vector at time t is
Maurinko [17]

1) The average velocity is -2.1\cdot 10^5 m/s

2) The instantaneous velocity is 64t-260t^3

Explanation:

1)

The average velocity of an object is given by

v=\frac{d}{t}

where

d is the displacement

t is the time elapsed

In this problem, the position of the particle is given by the function

x(t) = 32t^2 - 65t^4

where t is the time.

The position of the particle at time t = 6 sec is

x(6) = 32(6)^2 - 65(6)^4=-83,088 m

While the position at time t = 12 sec is

x(12)=32(12)^2-65(12)^4=-1,343,232 m

So, the displacement is

d=x(12)-x(6)=-1,343,232-(-83,088)=-1,260,144 m

And therefore the average velocity is

v=\frac{-1,260,144 m}{12 s- 6 s}=-2.1\cdot 10^5 m/s

2)

The instantaneous velocity of a particle is given by the derivative of the position vector.

The position vector is

x(t) = 32t^2 - 65t^4

By differentiating with respect to t, we find the velocity vector:

v(t) = x'(t) = 2\cdot 32 t - 4\cdot 65 t^3 = 64t - 260 t^3

Therefore, the instantaaneous velocity at any time t can be found by substituting the value of t in this expression.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

6 0
4 years ago
Two trains on separate tracks move toward each other. Train 1 has a speed of 125 km/h; train 2, a speed of 94.0 km/h. Train 2 bl
dexar [7]

Answer:

f_{o}=595.98Hz

Explanation:

Given data

Train 1 speed v₀=125 km/h =34.7222 m/s

Train 2 speed vs=94.0 km/h=26.1111 m/s

Speed of sound v=343 m/s

Train 2 frequency fs=500 Hz

To find

Frequency f₀ heard by engineer on train 1

Solution

We can use below formula to find the required frequency

f_{o}=f_{s}(\frac{v+v_{o}}{v-v_{s}} )\\f_{o}=(500Hz)(\frac{343m/s+34.722m/s}{343m/s-26.111m/s} ) \\f_{o}=595.98Hz

4 0
3 years ago
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