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2 years ago

9

Find the slope of the line. A: -2/3 B: 2/3 C: 3:2 D: -3/2

1 answer:

tia_tia [17]2 years ago

3 0

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (look at the picture) (0, 1) and (-2, -2). Substitute:

$m=\dfrac{-2-1}{-2-0}=\dfrac{-3}{-2}=\boxed{\dfrac{3}{2}}\to\boxed{D}$

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If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$

6 0

3 years ago

Read 2 more answers

Find the coordinates for the midpoint of the segment with endpoints given 12,4 and -8,8

borishaifa [10]

<h2>Hello!</h2>

The answer is:

The coordinates of the midpoint are:

$x-coordinate=2\\y-coordinate=6$

<h2>Why?</h2>

We can find the midpoint of the segment with the given endpoints using the following formula.

The midpoint of a segment is given by:

$MidPoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

We are given the points:

$(12,4)\\$

and

$(-8,8)\\$

Where,

$x_{1}=12\\y_{1}=4\\x_{2}=-8\\y_{2}=8$

So, calculating the midpoint, we have:

$MidPoint=(\frac{12+(-8)}{2},\frac{4+8}{2})$

$MidPoint=(\frac{4}{2},\frac{12}{2})$

$MidPoint=(2,6)$

Hence, we have that the coordinates of the midpoint are:

$x-coordinate=2\\y-coordinate=6$

Have a nice day!

8 0

2 years ago

Read 2 more answers

Jennifer left her house at 6:45 AM. It took her eight minutes 45 seconds to walk to the bus stop. She waited 3 3/4 Minutes for t

Kisachek [45]

Answer:

Step-by-step explanation:

7:05am

8 0

3 years ago

Question 16 (Essay Worth 7 points)<br><br> Verify the identity.<br><br> tan (x + π/2) = -cot x

Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

$\frac{sin(x+pi/2)}{cos(x+pi/2)}$

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

$\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)} = \frac{cos(x)}{cos(x+\pi/2) }$

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

$\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)$

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2 years ago

A deep sea diver is 4.5m below the water level At what depth he is now ? At what height is he now

oee [108]

Answer:

Step-by-step explanation:

Below the sea level should be mentioned by negative value

So, It is = - 4.5

7 0

2 years ago