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LenaWriter [7]
3 years ago
11

Find the value of x for which ABCD must be a parallelogram.

Mathematics
1 answer:
Inessa [10]3 years ago
3 0
Hey there!

You can tell that the two angles are congruent because of the arc. So make the two angles each other.
3x-17=25-3x. Add 3x to each side. You get 6x-17=25. Add 17 to each side to get 6x=42. Divide each side by 6. You get x=7. So the value of x would be 7.

I hope this helps!
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7 0
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The graph of f(x) = x^2 has been shifted into the form f(x) = (x − h)^2 + k
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\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see, it went to the right 2 units, and then up 3 units.

that simply means, C = -2, D = 3.
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3 years ago
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