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3 years ago

How can you use similar triangles to find the missing parts of a triangle?

Mathematics

2 answers:

REY [17]3 years ago

6 0

I think the blanks would be, "sides" and "angles."

ddd [48]3 years ago

3 0

The correct answer is proportionality and angles, little bro

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Help me with this please

Reika [66]

Answer:

$2,459.21

Step-by-step explanation:

(see attached for reference)

recall that the formula for compound interest is:

A = P [ 1 + (r/n)^ (nt) ]

where,

A = Final amount ( we are asked to find this)

P = principal amount = given as $2,340

r = Annual Interest Rate = given as 5% = 0.05

n = number of times compounded in a year = 4 (compounded quarterly)

t= time = 1 year

Substituting the values into the equation,

A = P [ 1 + (r/n)^ (nt) ]

A = 2,340 [ 1 + (0.05/4)^ (4·1) ]

A = $2,459.21

6 0

3 years ago

11) At a certain company, an HR benefits meeting and shareholders meeting happen at the same time, so it is impossible for an em

Airida [17]

Answer:

0.99

Step-by-step explanation:

The computation of the probability for employee goes for shareholder meeting or HR benefits meeting is

= Probability of HR benefits meeting + Probability of shareholder meeting

= 0.33 + 0.66

= 0.99

We simply added the both meeting probability i.e HR benefits and shareholder meeting so that the given probability could come

4 0

4 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$