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puteri [66]
3 years ago
10

Solve for w . =−28−4w simplify your answer as much as possible

Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0
In order to find the value for 'w', you will need to cancel out -4w by adding 4w from the right side to the left side. You will have a equation of 4w=-28, but you will also need to have 'w' by itself so you will divide -28 to 4. Your final answer is -7.
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April shoots an arrow upward into the air at a speed of 32 feet per second from a platform that is 11 feet high. The height of t
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Answer:

27 ft

the maximum height of the​ arrow is 27 ft

Step-by-step explanation:

Given;

The height of the arrow is given by the function;

h(t) = -16t^2 + 32t + 11

Maximum height is at point when dh(t)/dt = 0.

Differentiating h(t), we have;

dh/dt = -32t + 32 = 0

Solving for t;

-32t = -32

t = -32/-32 = 1

t = 1 (time at maximum height is t = 1)

Substituting t=1 into h(t), to determine the value of maximum height;

h(max)= -16(1^2) + 32(1) + 11

h(max) = 27 ft

the maximum height of the​ arrow is 27 ft.

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3 years ago
Need help please like I think I'm screwed
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