(4v-3w)∧2, Its to the second power so take the exponent 2 and put it on the variables and coefficients so you would have (4∧2)(v∧2)-(3∧2)(w∧2). Then you would do the math and get 16v∧2-9w∧2 than you would add the like terms so you have 25v∧2w∧2.
Answer:
Step-by-step explanation:
By doing dimensional analysis, we can easily calculate for what is being asked here. We do as follows:
Given:
Energy per time = 2400 BTU/hr
time period = 3 hrs
number of subjects = 7
Measurement of the weights = <span>20 ft × 25 ft × 12 ft
The energy produced for 3 hours would be:
2400 BTU/hr ( 3hr) = 7200 BTU
Volume of each weight = </span><span>20 ft × 25 ft × 12 ft = 6000 ft^3
Energy per volume = 7200 / 6000 = 1.2 BTU/ft^3
However, we have 7 bodybuilders producing this amount therefore,
Total energy produced = 7 (1.2 BTU/ft^3) = 8.4 BTU/ft^3</span>
Given,
SP~QP
SR~QR
In ∆SRP and ∆QRP
SP~QP (given)
SR~QR (given)
PR=PR (common)
Therefore,
∆SRP~∆QRP by SSS congruence rule.