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svp [43]
3 years ago
8

HURRY WILL GIVE BRAINIEST!!!!!

Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answers:

a) \frac{1}{64}

b) 27

c) 6^{20}

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When the factors of a trinomial are (x+p) and (x-q) then the coeffcient of the x term in the trinomial is?
Tatiana [17]
The coefficient is:  "1" .
____________________________________________________
          Note:  There is an "<u>implied coefficient</u>" of "1"; since "1",  multiplied by any value, is equal to that exact same value; by convention, we eliminate the "1" as a coefficient.
____________________________________
Further explanation:
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(x+p)(x−q) = x² − xq + px − pq ;
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(x+p)(x−q) =  {using "FOIL" → "First, Outer, Inner, and Last" terms}:
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<u>F</u>irst:    x*x = x² ;

<u>O</u>uter: x*(-q)= -xq ;

<u>I</u>nner:  p*x = px ;

<u>L</u>ast:   p*(-q) = -pq
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  (x + p)(x − q) = x² − xq + px − pq .
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4 0
3 years ago
Determine whether the relationship is a function. Complete the explanation.
8090 [49]

Answer:

the anser is d thank you for leting me anser have a good day

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3x(5x2)=(3x5)x2 which property of multiplication does the equation show
Natalija [7]
The Associative Property
8 0
3 years ago
For the real-valued functions f(x)=2x+3 and g(x)=√x-5, find the composition fog and specify its domain using interval notation.
Burka [1]

Find fog

  • fog(x)
  • f(g(x))
  • f(√x-5)
  • 2√(x-5)+3

For real range the domain

  • x-5≥0
  • x≥5

Domain is [5,oo)

7 0
2 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.9degreesf and a standard deviation of 0.67
trasher [3.6K]

Answer:

Step-by-step explanation:

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation = 0.67

n = number of samples = 103

From the information given, the population standard deviation is unknown hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 103 - 1 = 102

Since confidence level = 99% = 0.99, α = 1 - CL = 1 – 0.99 = 0.01

α/2 = 0.01/2 = 0.005

the area to the right of z0.005 is 0.005 and the area to the left of z0.005 is 1 - 0.005 = 0.995

Looking at the t distribution table,

z = 2.6249

Margin of error = 2.6249 × 0.67/√103

= 0.173

Confidence interval = 98.6 ± 0.173

This suggests that the mean body temperature could very possibly be

98.6degrees°F.

3 0
4 years ago
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