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Tema [17]
3 years ago
6

Historically, a certain region has experienced 65 thunder days annually. (A "thunder day" is day on which at least one instance

of thunder is audible to a normal human ear). Over the past eleven years, the mean number of thunder days is 55 with a standard deviation of 20. Can you conclude that the mean number of thunder days is less than 65? Use the a = 0.01 level of significance.
Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

No, we can't conclude that the mean number of thunder days is less than 65.

Step-by-step explanation:

We are given that Historically, a certain region has experienced 65 thunder days annually. Over the past eleven years, the mean number of thunder days is 55 with a standard deviation of 20.

We have to test that the mean number of thunder days is less than 65 or not.

Let, NULL HYPOTHESIS, H_0 : \mu \geq 65 days {means that the mean number of thunder days is higher than or equal to 65}

ALTERNATE HYPOTHESIS, H_1 : \mu < 65 days {means that the mean number of thunder days is less than 65}

The test statistics that will be used here is One-sample t-test;

               T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean number of thunder days = 55

              s = sample standard deviation = 20

              n = number of years = 11

So, <u>test statistics </u>= \frac{55-65}{\frac{20}{\sqrt{11} } }  ~ t_1_0

                             = -1.658

Now, at 1% significance level t table gives critical value of -2.764. Since our test statistics is higher than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the left side of critical value rejection region.

Therefore, we conclude that the mean number of thunder days is higher than or equal to 65.

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7m + 3mn when m = 8 and n = 14
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Answer:

392

Step-by-step explanation:

m = 8 and n = 14

Substituting the values of m and n in the question, we get :

7m + 3mn

=( 7 x 8) +(3 x 8 x 14)

= 56 + 336

= 392

8 0
3 years ago
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Ray industries bought a touchscreen monitor for $1200 it is expected to depreciate at a rate of 25% per year what was the value
max2010maxim [7]

So for this problem, we will be using the exponential equation format, which is y = ab^x. The a variable is the initial value, and the b variable is the growth/decay.

Since our touchscreen starts off at a value of 1200, that will be our a variable.

Since the touchscreen is decaying in value by 25%, subtract 0.25 (25% in decimal form) from 1 to get 0.75. 0.75 is going to be your b variable.

In this case, time is our independent variable. Since we want to know the value 3 years from now, 3 is the x variable.

Using our info above, we can solve for y, which is the cost after x years.

y=1200*0.75^3\\y=506

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7 0
3 years ago
please help 30 points !! in a proportional relationship when Y=2 when X=8 Which of the following equations would describe this r
Alex777 [14]

Answer:

(1)

Step-by-step explanation:

We will try:

(1) y = \frac{1}{4}x => 2 = 2 (seems legit)

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Answer:

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Step-by-step explanation:

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stich3 [128]

Answer:

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Step-by-step explanation:

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×     5

------------------

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Therefore, 12.7×5=63.5.

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