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asambeis [7]
4 years ago
11

Factorise this expression as fully as possible 14t^3 x 6t

Mathematics
1 answer:
kupik [55]4 years ago
6 0
14t^3*6t
= (14*6)*(t^3*t)
= (2*7*2*3)*(t*t*t*t)
= 2*2*3*7*t*t*t*t
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Please help ASAP please please
OLEGan [10]

Answer:

C

Step-by-step explanation:

0.38 = 19/50

Hope this helps!

8 0
3 years ago
Read 2 more answers
Thanks for your response!<br> Question will be show✔
algol13
<h3>Answer:</h3>

\large\boxed{-1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}}

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to put the numbers that were given from <em>least </em>to <em>greatest.</em>

Our given numbers are:

  • \frac{6}{40}
  • 0.35
  • 1\frac{3}{4}
  • -1\frac{16}{25}

Now, lets sort them out.

We know that negative numbers would be the least. Sicne there's only one negative number, we would put that first because it's the least out of the numbers.

\frac{6}{40} would go next. To make it easier, we can turn it into a decimal. \frac{6}{40} = 0.15 when you divide.

0.35 will go next. This would be bigger than 0.15, but lower than the next number.

1\frac{3}{4} would go last, due to the fact that it's the greatest. 1\frac{3}{4} is the same as 1.75

When you put them in order, you should get -1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
4 0
3 years ago
Venessa has scored 45 32 and 37 on her three math quizez she will take one more quiz and she wants a quiz average of at least 40
madreJ [45]

\frac{45 + 32 + 37 + x}{4}  = 40 \\ x = 46
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3 years ago
Which equation can you use to solve for figure shown?
DIA [1.3K]

Hey mate

Here is ur answer ...

I hope it'll help ....

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Maths Problem. I can't quite explain it, could you help please? Thanks for every good answer. All shown on the picture :)
Nimfa-mama [501]

This is something you would do through trial and error. At least, that's the approach I took. I'm not sure if there is any algorithm to solve. The solution I got is shown in the attached image below. There are probably other solutions possible. The trick is to keep each number separate but not too far away so that the other numbers to be filled in later don't get too crowded to their neighbor.

Side note: any mirror copy of what I posted would work as well since you can flip the page around and it's effectively the same solution.

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