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Tems11 [23]
4 years ago
11

If there is 4 green marbles and 7 orange marbles in box 1 and 4 green marbles and 5 orange marbles in box 2 what is the probabil

ity of picking 2 green marbles?
Mathematics
1 answer:
MrMuchimi4 years ago
6 0

Out of which box?

I'll answer for Box 1 and Box 2.

So in Box 1, you have 4 + 7 = 11 marbles in total.

Probability of drawing first marble green.

4 (green marbles) / 11 (marbles in total.

Probability of drawing second marble green:

Assuming you already drew a green marble, there's one less green marble, and one less marble in total:

3 / 10.

So the probability of drawing 2 green marbles in Box 1 is:

4 / 11 * 3/10 (since they're independent events) = 12/110 = 6/55

Probability of drawing 2 green marbles in Box 1 is: 6/55.

_______________________________

Now let's move on to Box 2:

You have 4 + 5 = 9 marbles in total.

Probability of drawing first marble green:

4 / 9.

Probability of drawing second marble green:

3/8

Multiply them since they're independent events:

4/9 * 3/8 = 12/72 = 6/36 = 1/6.

Probability of drawing 2 green marbles in Box 2 is 1/6.

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Answer:

2587mm^3 approx!

Step-by-step explanation:

first you divide the nut into 6 part(in triangle now, by joining centre to each edge)

let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height

i.e, 1/2×13×15=97.5(mm^2)

now when we consider depth of that traingular part,we will get volume of that part as area×depth

i.e, 97.5×6=585(mm^3)

now volume of all the 6 triangular part is 585×6=3510(in mm^3)

now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately

now reqired volume will be volume of that hexagonal part minus that of circular cavity

=3510-923

=2587mm^3

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3 years ago
Sue has 156 marbles. She lost 24 marbles. How many marbles does Sue have now?​
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4 years ago
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Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20, 0).
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C

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