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damaskus [11]
3 years ago
5

Write an expression that represents the area of a rectangle with length 4ab squared and width 2ab. (For any rectangle with lengt

h l and width w, A = lw.)
Mathematics
1 answer:
Drupady [299]3 years ago
8 0
The area of a rectangle is A=lw. Therefore, it can be represented here as: A=(4ab^2)(2ab).

Now, you can distribute.
4*2=8
a*a=a^2
b^2*b=b^3

The simplified expression is 8a^2b^3.

Hope this helps!!
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Find the rectangular coordinates of the point that has polar coordinates , 4, −3π/4
kirill115 [55]
Hello : 
 x= r cos<span>θ
 y= r sin</span><span>θ
r = 4   and  </span>θ =<span> −3π/4
cos( </span> −3π/4 )  = cos(  3π/4 ) = cos ( π - <span>π/4) = - cos (</span><span>π/4)= - </span><span>√2/2
</span>sin(  −3π/4 )  =  -  sin(  3π/4 ) = - sin ( π - π/4) = -sin (π/4)= - √2/2
x = - 2 √2
 y = - 2 √2

6 0
3 years ago
QUESTION 1<br> What is the mean of 21, 23, 35, 40)?<br> o A. 27<br> B. 31.75<br> e C. 19<br> D.29.75
tangare [24]

Answer:

D. 29.75

Step-by-step explanation:

To determine the mean, you must add up all the numbers and then divide that number by how many numbers you added.

Here,

21 + 23 + 35 + 40

= 119

You added 4 numbers (21, 23, 35, 40),

so, 119 / 4

= 29.75

Hope this helps and a thank won't hurt! :)

3 0
3 years ago
Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

4 0
3 years ago
About 13 out of 20 homes have a personal computer. On a street with 60 homes, how many would you expect to have a personal compu
Aleks04 [339]
This can be solved using a ratio. The ratio is: 13/20=x/60 this would then become 20x= 780  divide both sides by 20 and you get x=39. the answer is 39
5 0
3 years ago
Read 2 more answers
Graph the function.<br> y = 3 square root x
s2008m [1.1K]

Answer:

x=3×3

Step-by-step explanation:

ok it's fine if you don't mind

8 0
2 years ago
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