Answer:
The probability is ![P( p < 0.9207) = 0.0012556](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%200.0012556)
Step-by-step explanation:
From the question we are told
The population proportion is ![p = 0.96](https://tex.z-dn.net/?f=p%20%3D%200.96)
The sample size is ![n = 227](https://tex.z-dn.net/?f=n%20%20%3D%20%20227)
The number of graduate who had job is k = 209
Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is
![\mu_x = p = 0.96](https://tex.z-dn.net/?f=%5Cmu_x%20%3D%20p%20%3D%200.96)
Generally the standard deviation of this sampling distribution is
![\sigma = \sqrt{\frac{p (1 - p )}{n} }](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%20%281%20-%20p%20%29%7D%7Bn%7D%20%7D)
=> ![\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%20%5Csqrt%7B%5Cfrac%7B0.96%20%281%20-%200.96%20%29%7D%7B227%7D%20%7D)
=> ![\sigma = 0.0130](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%200.0130)
Generally the sample proportion is mathematically represented as
![\^ p = \frac{k}{n}](https://tex.z-dn.net/?f=%5C%5E%20p%20%3D%20%20%5Cfrac%7Bk%7D%7Bn%7D)
=> ![\^ p = \frac{209}{227}](https://tex.z-dn.net/?f=%5C%5E%20p%20%3D%20%20%5Cfrac%7B209%7D%7B227%7D)
=> ![\^ p = 0.9207](https://tex.z-dn.net/?f=%5C%5E%20p%20%3D%20%200.9207)
Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as
![P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%20P%28%20%5Cfrac%7B%5C%5E%20p%20-%20p%20%7D%7B%5Csigma%20%7D%20%3C%20%20%5Cfrac%7B0.9207%20-%200.96%7D%7B0.0130%20%7D%20%20%29)
![P( p < 0.9207) = P(Z< -3.022 )](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%20P%28Z%3C%20-3.022%20%29)
From the z table the area under the normal curve to the left corresponding to -3.022 is
![P(Z< -3.022 ) = 0.0012556](https://tex.z-dn.net/?f=P%28Z%3C%20-3.022%20%29%20%3D%200.0012556)
=> ![P( p < 0.9207) = 0.0012556](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%200.0012556)
Answer:11.7
Step-by-step explanation:
1. Recognize variables. Starting price is 9, it’s increasing by 1.5% each year, the question asks for the price in 20 years.
2. Convert percentage to decimal. Most calculators won’t understand multiplying by percentages, and instead will understand multiplying by decimals. A decimal is something we can easily work with. It is more commonly taught to work with decimals as well. With that said 1.5% equals .015. (The number in the ones place in the percentage is always in the hundredths place when converted to a decimal, the tens to the tenths, the hundreds in the percentage to the ones place in the decimal, the hundredths in the percentage to the ten thousandths in the decimal. Basically, every individual number [the 5 in 1.5] moves two spaces to the right when going from percentage to decimal form, likewise two to the left going from decimal to percentage form. 23%=.23, 104%=1.04, 0.5%=.05, 1.234%=.01234)
3. Make your equation
20(9*(.015))+9
+9 is your starting point
9*(.015) gives you the amount the price increases per year
20 is multiplied then to that increased price for the next 20 years
4. Crunch em numbers
PEMDAS
Given:
v = 150d
v represents company's production for the coming year
d represents the number of days
150 is the daily production
<span>The rate of change of the function representing the number of vehicles manufactured for the coming year is CONSTANT (150) , and its graph is a STRAIGHT LINE . So, the function is a LINEAR function. </span>
Puff trees smash freaks and eat between the cheeks
Answer:
option B
Step-by-step explanation:
we know:
area of a rectangle= b*h
in this case we have from the picture:
b=4
h=6
so we have:
area of a rectangle= 4*6
area of a rectangle= 24 square units