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VMariaS [17]
3 years ago
14

Gabe made a rectangular sandbox for his brother to play in. Gabe wants to paint only the sides of the sandbox. A prism has a len

gth of 4 feet, height of 1.5 feet, and width of 5 feet. What is the surface area of the sides of the sandbox that Gabe wants to paint? 27 ft2 30 ft2 47 ft2 60 ft2
Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer: The surface area of the sides of the sandbox that Gabe wants to paint is 47ft2

Step-by-step explanation:

Hi to answer this we have to apply the formula:

Surface Area of a rectangular prism = 2lw + 2wh + 2lh

Where:

l= length

w= width

h= height

Since the sandbox is open , it has one less surface (length x width), we have to add only one lw term.

Surface Area of the sandbox = lw + 2wh + 2lh

A = (4x5) + 2( 5x1.5) + 2( 4x1.5)

A = 20+15+12

A= 47 ft2

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Example: 1x+2y+3z+4a+5x+6y+7z+8+9

We can see that there is more than one number with the variable x, therefore, we say they're ''like terms'' and because of that they can be summed. We do this with all of the other numbers with similar variables. If no numbers with similar variables are left, like 4a, you don't do anything but write them as they are. You can also see that 8 and 9 can also be summed because neither of them has a variable, therefore they're similar.

In this step, you just do the operation with the numbers and keep the same variable.

(1x+5x)+(2y+6y)+(3z+7z)+4a+(8+9)

(6x)+(8y)+(10z)+4a+(17)

since there are not more numbers similar in variables, this operation is done.

6x+8y+10z+4a+17

8 0
2 years ago
Solve the equation.<br> у+ 3 = -у +9<br> y=1<br> y= 3<br> y= 6<br> y= 9
Anna007 [38]
The first y equals -3 and the second y equals -9
8 0
3 years ago
The equation below shows the total volume (V),in cubic units, of 2 identical boxes with each side equal to s units:
mrs_skeptik [129]
A. 21.0 cubic units
2 × 3.5 × 3
8 0
2 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7Bw%7D%7B3%7D%20" id="TexFormula1" ti
ElenaW [278]

Answer:  \bold{w=\dfrac{6y-3}{2}}

<u>Step-by-step explanation:</u>

Isolate w by performing the following steps

  • Multiply by 6 on both sides to clear the denominator
  • Subtract 3 from both sides
  • Divide both sides by 2

y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}

5 0
3 years ago
How would I start to solve this? <br> Y=-1/3-1
statuscvo [17]

Answer:

<em>Y = -4/3</em>

Step-by-step explanation:

Subtract 1 from -1/3.

Y = -1/3 - 1

Y = -1/3 - 3/3

Y = -4/3

6 0
2 years ago
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