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VMariaS [17]
3 years ago
14

Gabe made a rectangular sandbox for his brother to play in. Gabe wants to paint only the sides of the sandbox. A prism has a len

gth of 4 feet, height of 1.5 feet, and width of 5 feet. What is the surface area of the sides of the sandbox that Gabe wants to paint? 27 ft2 30 ft2 47 ft2 60 ft2
Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer: The surface area of the sides of the sandbox that Gabe wants to paint is 47ft2

Step-by-step explanation:

Hi to answer this we have to apply the formula:

Surface Area of a rectangular prism = 2lw + 2wh + 2lh

Where:

l= length

w= width

h= height

Since the sandbox is open , it has one less surface (length x width), we have to add only one lw term.

Surface Area of the sandbox = lw + 2wh + 2lh

A = (4x5) + 2( 5x1.5) + 2( 4x1.5)

A = 20+15+12

A= 47 ft2

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Maddie and her friends are making s'mores over the campfire. they have a bag of 48 marshmallows, 2 packs of graham crackers cont
VladimirAG [237]

The answer would be 16 S'mores and the limiting reactant would be the grahams.


(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)


Limiting reactant would be the reactant that runs out first.


Let's take your problem into account and see what we have:

48 marshallows

32 grahams (2 x 16 per pack)

45 chocolate pieces (5 x 15 pieces per bar)


Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.

The maximum yield of marshmallows is 48.

The maximum yield of chocolate is 45.


Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.

8 0
4 years ago
Helppppp plsssssss help
slava [35]
The answer is C. P=h + 11
4 0
3 years ago
a bicycle tire is 28 inches in diameter. approximately how far does the bicycle move forward each time the wheel goes around? (u
belka [17]

ANSWER

88 \: inches

EXPLANATION

The given bicycle has a tyre that is 28 inches in diameter.

How far the bicycle moves forward each time the wheel goes around is the circumference of the bicycle tyre.

This is calculated using the formula:

C =\pi \: d

We substitute the diameter and

\pi =  \frac{22}{7}

C =  \frac{22}{7}  \times 28

This simplifies to

C =22 \times 4

88 \: inches

8 0
3 years ago
Read 2 more answers
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

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3 years ago
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Answer:

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