What is the linear equation: y=-5x-3 in standard form

AlekseyPX

Answer: 4

Step-by-step explanation: Range is the difference between the highest and lowest number, so since 5 is the highest and 1 is the lowest you subtract 1 from 5 to get your answer: 4.

7 0

2 years ago

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A construction crew has repaired 1.37 miles of a highway. The total length of the highway to be repaired is 7.9. How many miles

JulijaS [17]

Answer:

Part A: m+1.37=7.9

Part B: 6.53 miles are left to be repaired.

Step-by-step explanation:

Given,

Length of repaired part = 1.37 miles

Total length to be repaired = 7.9 miles

Miles left to be repaired = m

Part A:

Create an equation to show the relationship between the number of miles repaired and the number of miles left to be repaired, m.

Miles left to be repaired + Length of repaired part = Total length to be repaired

m+1.37=7.9

Part B

How many miles are left to be repaired?

Subtracting 1.37 from both sides

6.53 miles are left to be repaired.

Keywords: length, subtraction

Step-by-step explanation:

6 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Can someone help me!<br> if something cost $4.90 due to a 14% discount what is the original price

Vlad [161]

Answer:

$4.21

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 4.9 × 14/100

Discount = 4.9 x 0.14

You save = $0.69

Final Price = Original Price - Discount

Final Price = 4.9 - 0.686

Final Price = $4.21

6 0

3 years ago

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An experiment consists of rolling two fair number cubes. What is the probability that the sum of the two numbers will be >3

liraira [26]

Answer: $\bold{\dfrac{5}{12}}$

<u>Step-by-step explanation:</u>

greater than 3 means the sum is either 4, 5, or 6.

There are 15 permutations that meet the criteria:

(1, 3), (1, 4), (1, 5), (1,6)

(2, 2), (2, 3), (2, 4), (2, 5), (2,6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3,6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4,6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5,6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6,6)

There are 6²= 36 total permutations for 2 dice.

$Probability=\dfrac{\#\ of\ permutations> 3}{total\ \#\ of\ permutations}\\\\.\qquad \qquad =\dfrac{15}{36}\\\\.\qquad \qquad =\dfrac{5}{12}\\\\$

3 0

3 years ago