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xenn [34]
3 years ago
13

You give me answer=BRAINLIEST

Mathematics
1 answer:
mamaluj [8]3 years ago
3 0

Answer:

A. 2

Step-by-step explanation:

Well let’s first graph the following,

x^2 + y = 8

x=y

So on the graph the system of equations only have 2 real solutions which are

(-3.272, -3.272) (2.372,2.372)

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The ordered pair (3,9) is a solution to the system of
nadya68 [22]

Answer:

(2,7) is not a solution to the given system of equations.

Step-by-step explanation:

Given system of equation is:

2x + 3 = y

2x + y = 15

To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.

Putting x=2 and y=7 in Eqn 1

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Thus the ordered pair satisfies the equation

Putting x=2 and y=7 in Eqn 2

2(2) + 7 = 15

4 + 7 = 15

11 ≠ 15

The ordered pair do not satisfy the second equation.

Hence,

(2,7) is not a solution to the given system of equations.

8 0
3 years ago
What is the volume of the cone below?
Elden [556K]

Answer:

V = 3408 pi  unit^3

Step-by-step explanation:

Volume  of a cone is given by

V = 1/3 pi r^2 h

We know the radius is 12 and the height is 71

V = 1/3 * pi * (12)^2 *71

V = 1/3 * pi * 144 *71

V = 3408 pi  unit^3

7 0
3 years ago
Read 2 more answers
Josie read 40 pages of a book in 50 minutes. How many pages could she read in two hours?​
pav-90 [236]

Answer:

96

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do I find the sum or the difference how do I find the sum or the difference in 4y + 3 - y - 2
notka56 [123]

Answer:

3y+1

Step-by-step explanation:

4y+3-y-2

3y+3-2

3y+1

you just have to combine like terms

3 0
3 years ago
Davis Construction is building a new housing development. They begin by mapping the development out on a coordinate grid. They p
Mandarinka [93]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -4}}\quad ,&{{ -1}})\quad 
%  (c,d)
&({{ 6}}\quad ,&{{ 3}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ 6}} -4}{2}\quad ,\quad \cfrac{3-1}{2} \right)
3 0
3 years ago
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