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kirill115 [55]
3 years ago
6

Can you factor -2x + 6 to get -2(x - 3)

Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

Divide -2x + 6 by -2, then bring the -2 outside the bracket

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What is the system solution to 8x + 7y = 39
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-8/7

Step-by-step explanation:

I thinks this is the answer

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Your friend’s heart beats 18 times in 15 seconds when at rest. While running, your friend’s heart beats 25 times in 10 seconds.
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72 times at rest and 250 while running.
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3 years ago
Having a problem solving for h in this algebra problem. A=1/2h(B+b); A=35, B=6, b=1 <br> So h=?
ivann1987 [24]
35 = 1/2h (6+1)
35 = 1/2 h + 7
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8 0
2 years ago
Read 2 more answers
Mona stopped at a gas station where the price per gallon was $2.80. She spent $14 to fill up her car. What equation would repres
alina1380 [7]

Answer:

A.) 5 x 2.80 B.) 100

Step-by-step explanation:

14/2.80=5 which is how many gallons

5 x 20 = 100 for the miles

8 0
2 years ago
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The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
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