Average speed =
(total distance)/(total time)
Average speed = (99+90)/(2+3)
That's (189 km) / (5 hr)
Average speed = 37.8 km/hr
Answer:
a) Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.
b) The total distance traveled by the baseball was 108.7 m.
Explanation:
a) To know if the hit was a home run we need to calculate the height of the ball at 99 m:

Where:
: is the final height =?
: is the initial height = 1 m
: is the initial vertical velocity = v₀sin(45)
v₀: is the initial velocity = 32.5 m/s
g: is the gravity = 9.81 m/s²
t: is the time
First, we need to find the time by using the following equation:

Now, the height is:
Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.
b) To find the distance traveled by the baseball first we need to find the time of flight:



By solving the above quadratic equation we have:
t = 4.73 s
Finally, with that time we can find the distance traveled by the baseball:

Hence, the total distance traveled by the baseball was 108.7 m.
I hope it helps you!
<span>"Time is like wax, dripping from a candle flame. In the moment, it is molten and falling, with the capability to transform into any shape. Then the moment passes, and the wax hits the table top and solidifies into the shape it will always be. It becomes the past, a solid single record of what happened, still holding in its wild curves and contours the potential of every shape it could have held."</span>
Answer:
T ambient = 10 degrees
Explanation:
Using Newton's Law of Cooling:
T(t) = Tamb + (Ti - Tamb)*e^(-kt) ..... Eq 1
Ti = 100
We have two points to evaluate the above equation as follows:
T = 70 @ t = 10 using Eq 1
70 = Tamb + (100 - Tamb)*e^(-10k) ... Eq 2
T = 50 @ t = 20 using Eq 1
50 = Tamb + (100 - Tamb)*e^(-20k) ... Eq 3
Solving the above Eq 2 and Eq 3 simultaneously:
Using Eq 2:
(70 - Tamb) / (100 - Tamb) = e^(-10k)
Squaring both sides we get:
((70 - Tamb) / (100 - Tamb))^2 = e^(-20k) .... Eq 4
Substitute Eq 4 into Eq 3
50 = Tamb + (100 - Tamb)*((70 - Tamb) / (100 - Tamb))^2
After simplification:
50 = (Tamb (100-Tamb) + (70-Tamb)^2) / (100 - Tamb)
5000 - 50*Tamb = 4900 - 40*Tamb
Tamb = 100 / 10 = 10 degrees
Answer:
c = 5 m
Explanation:
this exercise you want to divide the rectangular room into two triangular rooms
the area of triangles is
A = ½ base height
A = ½ 4 3
A = 6 m²
the length of the curtain can be found using the Pythagorean theorem
c² = b² + a²
c = √ (4² + 3²)
c = 5 m
this is the length of the curtain