We can decompose the problem on x- and y-axis.
The position vector decomposed is:


The velocity vector can be found computing the derivative of r on both axes:


So, the velocity vector is
r' = 1
i+2at
j
The speed (the magnitude of the velocity vector) is

Finally we can write the acceleraion vector by performing derivation on the velocity vector:


and so
r''=2a
j
This is b. false
There are numerous ways of adjusting the forehand stroke and variations are allowed.
Answer: 0.42 watts
Explanation:
Given that:
power = ?
energy =500 joules
time = 1200 seconds
Recall that power is the rate of energy expended per unit time
i.e Power = energy / time
Power = 500J / 1200seconds
Power = 0.416 watts (rounded to the nearest hundredth as 0.42 watts)
Thus, the power of the instrument is 0.42 watts
Answer:
The ones that are after the light that went out are also out.
Explanation:
In that case, their momentum must be equal.
So, m1v1 = m2v2
20 * 20 = 40 * v2
v2 = 400 / 40
v2 = 10
In short, Your Answer would be: 10 m/s
Hope this helps!