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frosja888 [35]
4 years ago
12

Solve for x 3{x-2}+1=3x-5

Mathematics
2 answers:
Mars2501 [29]4 years ago
8 0
Yes the equation has infinitely many solutions I solved it also
umka21 [38]4 years ago
5 0
Multiply out the product on the left side:

<span>3{x-2}+1=3x-5 becomes 3x-6 + 1 = 3x -5
                                         3x-5      = 3x - 5

This is always true, regardless of the value of x.  Thus, this equation has infinitely many solutions.</span>
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What ratios are equivalent to 4:3?<br> 7:2<br> 12/42<br> 28:21<br> 42:12
Karolina [17]
28:21

because the same number has to multiply both sides of the ratio. so number = 7 and:
4x 7 = 28
3 x 7 = 21
3 0
3 years ago
5/9 4.9 meters tall ratio
Keith_Richards [23]
5 + 9 = 14

4.9 / 14 = 0.35

0.35 * 5 = 1.75

0.35 * 9 = 3.15

The answer is 1.75 / 3.75
8 0
3 years ago
What is the distance between (-3,-5) and (-3, 2)?
shusha [124]

Answer: 7 units

Step-by-step explanation:

Just plot the numbers, then count the distance between them

7 0
3 years ago
Given the point (-3, 6) and a line y=2x-8, write an equation of a line through the point and parallel to the line.
ch4aika [34]

Answer: y = 2x

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

y = 2x - 8

Comparing with the slope intercept form, slope = 2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 3,-6) is 2

To determine the intercept, we would substitute m = 2, x = - 3 and

y = - 6 into y = mx + c. It becomes

- 6 = 2 × - 3 + c

- 6 = - 6 + c

c = - 6 + 6 = 0

The equation becomes

y = 2x

7 0
3 years ago
The circle will be enlarged by a scale factor of 4.
sertanlavr [38]

Answer:

The area of the new circle is  144\pi \ in^2

Step-by-step explanation:

Given:

radius of the circle = 3 in.

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared.

Let

z-----> the scale factor

x-----> the area of the enlarged circle

y-----> the area of the original circle

So;

z^2= \frac{x}{y}

In this problem we have

z=4 ----> the scale factor

The area of the original circle is equal to

y = \pi r^2= \pi (3)^2= 9\pi \ in^2

Now substituting value of y and solve for x we get;

4^2=\frac{x}{9\pi}\\ \\x= 16\times9\pi= 144\pi \ in^2

Hence Area of the new Circle is 144\pi \ in^2

Also The area of the enlarged circle is 16 times the area of the original circle.

4 0
4 years ago
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