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Akimi4 [234]
3 years ago
10

What is the greatest common factor of 8x and 40?

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
3 0

Answer:5

Step-by-step explanation:

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As part of a survey, 150 students were asked to name their favorite class. 50 points
disa [49]
A:40%
If you put 60 over 150 and x(percent of students) over 100 and cross multiply 100 and 60, you will get 6000. You then divide that by 150 which leaves you with 40 as x and 40 over 100 is 40%.
5 0
2 years ago
Solve 2 + 3et+ 2 = 7 for x.
Evgen [1.6K]
It’s the answer 6x2=-7
5 0
3 years ago
If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

5 0
3 years ago
Find the polar equation of the conic with the focus at the pole, directrix x = 4, and eccentricity 1.
BabaBlast [244]

Answer:

Choice D is correct

Step-by-step explanation:

The eccentricity of the conic section is 1, implying we are looking at a parabola. Parabolas are the only conic sections with an eccentricity of 1.

Next, the directrix of this parabola is located at x = 4. This implies that the parabola opens towards the left and thus the denominator of its polar equation contains a positive cosine function.

Finally, the value of k in the numerator is simply the product of the eccentricity and the absolute value of the directrix;

k = 1*4 = 4

This polar equation is given by alternative D

6 0
2 years ago
Solve for x. -4≤2x+6<12
-BARSIC- [3]

-4≤2x+6<12

-6        -6   -6

-10≤2x<6

-6             -6

-15≤2x

-15÷2x=-7.5

2÷2=x

7.5=x

7 0
3 years ago
Read 2 more answers
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