What is the greatest common factor of 8x and 40?

For a population with an unknown distribution, the form of the sampling distribution of the sample mean is _____. Group of answe

Nesterboy [21]

For a population where the distribution is unknown, the sampling distribution of the sample mean will be b which is approximately normal for all sample sizes.

Given options regarding sample sizes.

We have to choose the correct option which shows the sample mean characteristics when the distribution is unknown.

Based on the central limit theorem the sampling distribution of the sample mean for either skewed variable ir normally distributed variable can be approximated given the mean and standard deviation.

The central limit theorem is said to be true when n greater than or equal to 30.

When n is greater than 30 ,z test is used, when n is less than 30 ,t test is used.

Hence for a population where the distribution is unknown ,the sampling distribution of the sample mean will be approximately normal for all sample sizes.

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Question is incomplete as it includes options in a right way:

1)exactly normal for large sample,

2) approximately normal for all sample sizes,

3) exactly normal for all sample sizes.

6 0

2 years ago

Please help I need help

FinnZ [79.3K]

Answer:

its option 3;92667

Step-by-step explanation:

6 and 8 is 68 so 9 2667 its 92667

3 0

3 years ago

I NEED HELP WITH A PROBLEM

Lapatulllka [165]

Answer:

39

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A bakery uses 550 pounds of sugar to make 1,000 cookies. Each cookie contains the same amount of sugar. How many pounds of sugar

Sonja [21]

Answer:

do da dash in the whip fo i fu6 a nica bih

Step-by-step explanation:

8 0

3 years ago

A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is

Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

$M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}$

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k" (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

$M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N} = \frac{(x_1 + x_2 + ... + x_n)}{N} = M$

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

$SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }$

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0

3 years ago