Answer:
<h2><em><u><</u></em><em><u>ABT</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em></h2><h2><em><u><</u></em><em><u>TBC</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em></h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u>, </u></em>
Line BT is the bisector of <ABC
<em><u>So</u></em><em><u>,</u></em>
3x + 13 = 5x - 7
=> 13 + 7 = 5x - 3x
=> 20 = 2x
![= > x = \frac{20}{2}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20x%20%3D%20%20%5Cfrac%7B20%7D%7B2%7D%20)
=> x = 10
<em><u>As</u></em><em><u>,</u></em><em><u> </u></em>
We got the value of <em><u>x = 10</u></em>
<em><u>Therefore</u></em><em><u>, </u></em>
<em><u><ABT</u></em> = 3x + 13 °
= 3×10 + 13 °
= 30 + 13°
= <em><u>43°</u></em>
<em><u><TBC</u></em> = 5x - 7°
= 5 × 10 - 7°
= 50 - 7°
= <em><u>43°</u></em>
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>Value</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u><</u></em><em><u>ABT</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>value</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u><</u></em><em><u>TBC</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>43</u></em><em><u>°</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Answer:
See below.
Step-by-step explanation:
Start with triangle ABC with side BC lying on line n.
Draw a line through point A parallel to line n, and call it line m.
Angles 1 and 3 are alternate interior angle of parallel lines and are congruent.
Angle 2 and 4 are alternate interior angles of parallel lines and are congruent.
The sum of the measures of angles angles 1, BAC, and 2 is 180 since they lie on a line.
m<1 + m<BAC + m<2 = 180
Now we substitute in the angles we know are congruent by alternate interior angles (written above).
m<3 + m<BAC + m<4 = 180
33
Step-by-step explanation:
The slope of a line is (change in y)/(change in x), so we can plug it in to here to get (11/5-6)/(3/16-1/10). It doesn't matter which y value you subtract from, but just make sure that the number you subtract from in both the numerator and denominator is from the same point!